Optimal. Leaf size=122 \[ \frac {\sqrt {1-2 x} (5 x+3)^{5/2}}{7 (3 x+2)^3}-\frac {15 \sqrt {1-2 x} (5 x+3)^{3/2}}{196 (3 x+2)^2}-\frac {495 \sqrt {1-2 x} \sqrt {5 x+3}}{2744 (3 x+2)}-\frac {5445 \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right )}{2744 \sqrt {7}} \]
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Rubi [A] time = 0.03, antiderivative size = 122, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {96, 94, 93, 204} \[ \frac {\sqrt {1-2 x} (5 x+3)^{5/2}}{7 (3 x+2)^3}-\frac {15 \sqrt {1-2 x} (5 x+3)^{3/2}}{196 (3 x+2)^2}-\frac {495 \sqrt {1-2 x} \sqrt {5 x+3}}{2744 (3 x+2)}-\frac {5445 \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right )}{2744 \sqrt {7}} \]
Antiderivative was successfully verified.
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Rule 93
Rule 94
Rule 96
Rule 204
Rubi steps
\begin {align*} \int \frac {(3+5 x)^{3/2}}{\sqrt {1-2 x} (2+3 x)^4} \, dx &=\frac {\sqrt {1-2 x} (3+5 x)^{5/2}}{7 (2+3 x)^3}+\frac {15}{14} \int \frac {(3+5 x)^{3/2}}{\sqrt {1-2 x} (2+3 x)^3} \, dx\\ &=-\frac {15 \sqrt {1-2 x} (3+5 x)^{3/2}}{196 (2+3 x)^2}+\frac {\sqrt {1-2 x} (3+5 x)^{5/2}}{7 (2+3 x)^3}+\frac {495}{392} \int \frac {\sqrt {3+5 x}}{\sqrt {1-2 x} (2+3 x)^2} \, dx\\ &=-\frac {495 \sqrt {1-2 x} \sqrt {3+5 x}}{2744 (2+3 x)}-\frac {15 \sqrt {1-2 x} (3+5 x)^{3/2}}{196 (2+3 x)^2}+\frac {\sqrt {1-2 x} (3+5 x)^{5/2}}{7 (2+3 x)^3}+\frac {5445 \int \frac {1}{\sqrt {1-2 x} (2+3 x) \sqrt {3+5 x}} \, dx}{5488}\\ &=-\frac {495 \sqrt {1-2 x} \sqrt {3+5 x}}{2744 (2+3 x)}-\frac {15 \sqrt {1-2 x} (3+5 x)^{3/2}}{196 (2+3 x)^2}+\frac {\sqrt {1-2 x} (3+5 x)^{5/2}}{7 (2+3 x)^3}+\frac {5445 \operatorname {Subst}\left (\int \frac {1}{-7-x^2} \, dx,x,\frac {\sqrt {1-2 x}}{\sqrt {3+5 x}}\right )}{2744}\\ &=-\frac {495 \sqrt {1-2 x} \sqrt {3+5 x}}{2744 (2+3 x)}-\frac {15 \sqrt {1-2 x} (3+5 x)^{3/2}}{196 (2+3 x)^2}+\frac {\sqrt {1-2 x} (3+5 x)^{5/2}}{7 (2+3 x)^3}-\frac {5445 \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {3+5 x}}\right )}{2744 \sqrt {7}}\\ \end {align*}
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Mathematica [A] time = 0.05, size = 74, normalized size = 0.61 \[ \frac {\frac {7 \sqrt {1-2 x} \sqrt {5 x+3} \left (2195 x^2+1830 x+288\right )}{(3 x+2)^3}-5445 \sqrt {7} \tan ^{-1}\left (\frac {\sqrt {1-2 x}}{\sqrt {7} \sqrt {5 x+3}}\right )}{19208} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.89, size = 101, normalized size = 0.83 \[ -\frac {5445 \, \sqrt {7} {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )} \arctan \left (\frac {\sqrt {7} {\left (37 \, x + 20\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{14 \, {\left (10 \, x^{2} + x - 3\right )}}\right ) - 14 \, {\left (2195 \, x^{2} + 1830 \, x + 288\right )} \sqrt {5 \, x + 3} \sqrt {-2 \, x + 1}}{38416 \, {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 2.07, size = 310, normalized size = 2.54 \[ \frac {1089}{76832} \, \sqrt {70} \sqrt {10} {\left (\pi + 2 \, \arctan \left (-\frac {\sqrt {70} \sqrt {5 \, x + 3} {\left (\frac {{\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}^{2}}{5 \, x + 3} - 4\right )}}{140 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}\right )\right )} - \frac {605 \, \sqrt {10} {\left (9 \, {\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{5} + 6720 \, {\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{3} - \frac {203840 \, {\left (\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}\right )}}{\sqrt {5 \, x + 3}} + \frac {815360 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}}{1372 \, {\left ({\left (\frac {\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}{\sqrt {5 \, x + 3}} - \frac {4 \, \sqrt {5 \, x + 3}}{\sqrt {2} \sqrt {-10 \, x + 5} - \sqrt {22}}\right )}^{2} + 280\right )}^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.02, size = 202, normalized size = 1.66 \[ \frac {\sqrt {5 x +3}\, \sqrt {-2 x +1}\, \left (147015 \sqrt {7}\, x^{3} \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )+294030 \sqrt {7}\, x^{2} \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )+30730 \sqrt {-10 x^{2}-x +3}\, x^{2}+196020 \sqrt {7}\, x \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )+25620 \sqrt {-10 x^{2}-x +3}\, x +43560 \sqrt {7}\, \arctan \left (\frac {\left (37 x +20\right ) \sqrt {7}}{14 \sqrt {-10 x^{2}-x +3}}\right )+4032 \sqrt {-10 x^{2}-x +3}\right )}{38416 \sqrt {-10 x^{2}-x +3}\, \left (3 x +2\right )^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.20, size = 107, normalized size = 0.88 \[ \frac {5445}{38416} \, \sqrt {7} \arcsin \left (\frac {37 \, x}{11 \, {\left | 3 \, x + 2 \right |}} + \frac {20}{11 \, {\left | 3 \, x + 2 \right |}}\right ) + \frac {\sqrt {-10 \, x^{2} - x + 3}}{63 \, {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )}} - \frac {235 \, \sqrt {-10 \, x^{2} - x + 3}}{1764 \, {\left (9 \, x^{2} + 12 \, x + 4\right )}} + \frac {2195 \, \sqrt {-10 \, x^{2} - x + 3}}{24696 \, {\left (3 \, x + 2\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\left (5\,x+3\right )}^{3/2}}{\sqrt {1-2\,x}\,{\left (3\,x+2\right )}^4} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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